SEATTLE, Wash. – Seattle is the USA’s most expensive destination for this upcoming Labor Day weekend, based on the cost of its lodging, according to a new survey. The survey compared hotel rates for 20 popular U.S. destinations for the Labor Day weekend period spanning August 31 to September 3 (Labor Day).
Travelers to Seattle over the long final weekend that unofficially brings summer to a close will have to pay at least $312 per night. And that’s for the cheapest available 3-star hotel room. This nightly rate makes Washington State’s largest city the priciest destination for this year’s Labor Day weekend. The runners-up are both found beachside on the East Coast in Virginia Beach and Atlantic City. There, room rates are $309 and $286 per night, respectively, for the cheapest available room.
What is contributing to Seattle’s most expensive status? Certainly the annual Bumbershoot Festival, which takes place over the Labor Day weekend, is playing a part. This music and arts festival typically drives around 100,000 visitors to the city each year. As a result of its popularity, hotel rates are around 65% higher than normal, according to the survey.
Budget travelers can find much more affordable rates at other national destinations, though. In Washington, DC or Miami Beach, for example, they can score a 3-star hotel room for around $100 per night. And the usually in-demand Orlando is a bargain hunter’s dream. In fact, it’s the country’s cheapest Labor Day weekend destination according to the survey, with an overnight rate of only $63.
The following table shows the 10 most expensive destinations in the United States for this year’s Labor Day weekend. The prices shown are based on the daily rate for each accommodation’s cheapest available double room (minimum 3-star hotel) for the time period of August 31 through September 3.
Virginia Beach $309
Atlantic City $286
New York City $224
San Francisco $179